(y+2)^2/3=y+2+(y^2)/3

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Solution for (y+2)^2/3=y+2+(y^2)/3 equation: 



(y+2)^2/3=y+2+(y^2)/3

We move all terms to the left:

(y+2)^2/3-(y+2+(y^2)/3)=0

determiningTheFunctionDomain
-(y+2+y^2/3)+(y+2)^2/3=0

We get rid of parentheses

-y^2/3-y+(y+2)^2/3-2=0

We multiply all the terms by the denominator


-y^2-y*3+(y+2)^2-2*3=0

We add all the numbers together, and all the variables

-1y^2-y*3+(y+2)^2-6=0

Wy multiply elements

-1y^2-3y+(y+2)^2-6=0

We move all terms containing y to the left, all other terms to the right

-1y^2-3y+(y+2)^2=6

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